Professional LINQ

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Scott Klein

"Professional LINQ"

This method also takes an overload, which returns all of the descendants that have the specified name,
as this code illustrates:
IEnumerable des =
from el in root.Descendants("Employeee")
select el;
foreach (XElement el in des)
listBox1.Items.Add(el.Name);
163
Part II: LINQ to XML
This example asks for the descendants of the Employee node, returning the following:
Name
Again, you could write the example as follows:
IEnumerable des = root.Descendants("Employeee");
foreach (XElement el in des)
listBox1.Items.Add(el.Name);
Just to make things a bit more complicated, let??™s add another employee and return the values of the
descendants of the employee node, which in essence is asking for the value of the Name node because it is
a descendant of the Employee node:
XElement root = new XElement("Employees",
new XElement("Employee",
new XElement("Name", "Scott"))
,
new XElement("Employee",
new XElement("Name", "Bob"))
);
textBox1.Text = root.ToString();
IEnumerable des = root.Descendants("Employee");
foreach (XElement el in des)
listBox1.

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An Account of the Customs and Manners of the Micmakis and Maricheets Savage Nations, Now Dependent on the Government of Cape-Breton (page 124) Danny's Own Story (page 114) Mrs. Falchion, Volume 2. (page 181)

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Scott Klein

"Professional LINQ"