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7 Sending an Ajax Request with Yahoo Search Web Services 215
if (window.XMLHttpRequest) {
return new XMLHttpRequest();
} else if (window.ActiveXObject) {
return new ActiveXObject(???Microsoft.XMLHTTP???);
}
}
var
url=???servlet/yahoo?appid=QwDUK7DV34H98YaFWsa3gHt.P68u
PPI7ThU92omV19uT85g9CAyqBUGmx.8eTF0-???+
???&query=???+encodeURI(document.getElementById(???query???).
value)+
???&results=???+encodeURI(document.getElementById(???result
s???).value)+
???&context=???+encodeURI(document.getElementById(???contex
t???).value);
xmlHttpRequest.open(???GET???, url, true);
xmlHttpRequest.onreadystatechange=processRequest;
xmlHttpRequest.send(null);
function processRequest(){
if(xmlHttpRequest.readyState==4){
if(xmlHttpRequest.status==200){
processResponse();
}
}
}
function processResponse(){
var xmlMessage=xmlHttpRequest.responseXML;
var
searchResults=document.getElementById(???searchResults???
);
var resultHtml="

";
var
resultList=xmlMessage.getElementsByTagName(???Result???);
var len =resultList.length;
for(var i=0; ivar result=resultList[i];
var
title=result.getElementsByTagName(???Title???)[0].firstCh
ild.nodeValue;
var
summary=result.getElementsByTagName(???Summary???)[0].fir
stChild.nodeValue;
var
url=result.getElementsByTagName(???Url???)[0].firstChild.
nodeValue;
resultHtml+=???
1. Title:???+??????
   +title+ ???
\n???;
216 10 Web Search with Ajax
resultHtml+=???Summary: ???+summary+??????;
}
resultHtml+=???

???;
searchResults.


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